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olga_2 [115]
3 years ago
11

Function f is a cosine function with period 8π, amplitude 3, and a local maximum at f(0) = –3. What is the equation of the midli

ne of the graph of f?
Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0

Answer:

y = 0

Step-by-step explanation:

Since there is no indication of a shift in the graph of f(x) = 3cos(-0.25x), then the midline must be the normal midline for a cosine or sine function which is: y = 0.

Lana71 [14]3 years ago
8 0

Answer: Is there suppose to be a picture or something?

Step-by-step explanation:

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What is the value of :-<br><br>=》<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20-%204%7D%7B5%20-%205%7D%20" id="TexFormu
Tresset [83]

Answer:

the value is undefined

Step-by-step explanation:

hey there,

->

\frac{4 - 4}{5 - 5}

->

\frac{0}{0}

0 divided by 0 is undefined

4 0
2 years ago
Solve The equation and check the solution expressed numbers as integers or simplified fractions
Lelechka [254]

Answer: m = - \frac{1}{40} \\

Step-by-step explanation:

I know this because I'm built different (FR FR This answer is correct)

8 0
3 years ago
What is the maximum value of the objective function, P, with the given constraints?
maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

P=20x+35y

Constraints,

x+y \leq 12

5x+y \leq 20\\x \geq 0\\y \geq 0

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

P=20x+35y

  • Point (0,0)

P=20(0)+35(0)=0

P=20x+35y

  • Point (0,12)

P=20(0)+35(12)=420

  • Point (2,10)

P=20(2)+35(10)=40+350=390

  • Point (4,0)

P=20(4)+35(0)=80

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0
3 years ago
Anyone know answer for number 4? My brain just isn’t working today hahaa
Dima020 [189]

Answer:

y=-6/5x + 1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What set of reflections would carry hexagon ABCDEF onto itself?
Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

First; we test the given options, until we get the true option

<u>(a) y=x, x-axis, y=x, y-axis</u>

The rule of reflection y =x is:

(x,y) \to (y,x)

The rule of reflection across the x-axis is:

(x,y) \to (x,-y)

So, we have:

(y,x) \to (y,-x)

The rule of reflection y =x is:

(x,y) \to (y,x)

So, we have:

(y,-x) \to (-x,y)

Lastly, the reflection across the y-axis is:

(x,y) \to (-x,y)

So, we have:

(-x,y) \to (x,y)

So, the overall transformation is:

(x,y) \to (x,y)

Notice that, the original and final coordinates are the same.

This means that:

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

Read more about reflections at:

brainly.com/question/938117

4 0
2 years ago
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