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lions [1.4K]
3 years ago
6

GIVING BRAINLIEST i know it aint math but no one does the buisness subject

Mathematics
2 answers:
Setler79 [48]3 years ago
5 0

Answer:

Post secondary

Step-by-step explanation:

Sorr if itswrong

snow_lady [41]3 years ago
3 0

Answer:

           

Step-by-step explanation:

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Help meeeeeeeeeeeeeeeeeeeeeee !!!!!
stiv31 [10]

Answer:

i think it is the 2nd one and the 5th one.

Step-by-step explanation:

hope this helped!

p.s it would be cool if you gave me brainliest

6 0
3 years ago
To be considered as a menu item for Gloria's new restaurant an item must have scored in the top 15% by the food critics in the a
vladimir1956 [14]

Answer:

Lowest score needed=4.92

Step-by-step explanation:

Using the standard normal distribution table we find the value of standard normal deviate corresponding to area of 15%

For area of 15% we have Z= -1.04

Thus we have

Z=\frac{X-\overline{X}}{\sigma }\\\\\therefore X=\sigma Z+\overline{X}\\\\

Applying values we get

X=-1.04\times 2+7\\\\X=4.92

Thus lowest score needed = 4.92

3 0
3 years ago
How far can jovan run in a full hour
yKpoI14uk [10]
2/3(4/3)= 8/9

Jovan ran 8/9 of a mile in a full hour.

Hope this helps!
4 0
3 years ago
The average of 25, 29, and x is 29. Find x.
Andrej [43]
X is going to equal 33. 25+29+x/3=33
8 0
3 years ago
Read 2 more answers
Find the system of inequalities which represents the shaded region on the coordinate plane.
dybincka [34]

Answer:

given, y≥2x+1 and

y>

2

1

x−1

first, draw the graph for equations y=2x+1 and y=

2

1

x−1

for y=2x+1

substitute y=0 we get, 2x+1=0⟹x=−0.5

substitute x=0 we get, y=1

therefore, y=2x+1 line passes through (0.5,0) and (0,1) as shown in fig.

Hence, y≥2x+1 includes the region above the line.

for y=

2

1

x−1

substitute y=0 we get,

2

1

x−1=0⟹x=2

substitute x=0 we get, y=−1

therefore, y=2x+1 line passes through (2,0) and (0,-1) as shown in fig.

Hence, y>

2

1

x−1 includes the region above the line.

the intersection region is the shaded region as shown in above figure which includes I, II and III quadrants.

Therefore, quadrant IV has no solution please make as brainlelist

7 0
3 years ago
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