Answer:
33.
Step-by-step explanation:
Since they are both primes, the least common factor of 11 and 3 is 11 times 3, which is 33. Therefore, Camryn will practice the trumpet and flute on the same day 33 days in the future.
Answer:
800
Step-by-step explanation:
Answer:
The required probability is 0.6517
Step-by-step explanation:
Consider the provided information.
North Catalina State University's students can be approximated by a normal model with mean 130 and standard deviation 8 points.
μ₁ = 130 and σ₁ = 8
Chapel Mountain University's students can be approximated by a normal model with mean 120 and standard deviation 10 points.
μ₂ = 120 and σ₂ = 10
As both schools have IQ scores which is normally distributed, distribution of this difference will also be normal with a mean of μ₁-μ₂ and standard deviation will be 
Therefore,
μ = 130-120=10

Now determine the probability of North Catalina State University student's IQ is at least 5 points higher than the Chapel Mountain University student's IQ:


Now by using the z table we find the z- score of -0.39 is 0.6517.
Hence, the required probability is 0.6517
Answer:
Circular one
Step-by-step explanation:
It really depends on how you cut it, but circles are just one big edge that's curved to meet up with itself.
Also, corners aren't edges and rectangles have corners.
Go with the circle one
<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
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Explanation:
We want to avoid having a negative number under the square root. Solving
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).