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Stells [14]
3 years ago
9

What formula can you use to find the lengths of a base and height of a triangle

Mathematics
2 answers:
melamori03 [73]3 years ago
6 0
L•w•h is the formula
mash [69]3 years ago
4 0

Answer:

W times H

Step-by-step explanation:

You might be interested in
15 is 9 more than j.
Zina [86]

Answer:

j = 6

Step-by-step explanation:

"Is" typically means equals. "More than" means it is added to.

So 15 equals j with 9 added to it.

15 = 9 + j

Now solve for j by subtracting 9 from both sides.

15 - 9 = j

j = 6

7 0
4 years ago
Read 2 more answers
What's the least common multiple of 8, 11, and 12?
Lena [83]
8 = 2 x 2 x 2
11 = 11
12 = 2 x 2 x 3

LCM = 2 x 2 x 2 x 3 x 11 = 264
7 0
3 years ago
Answer 7x9-8+11-6[5+2(-3)]
Anna [14]
I got 0.

First you look at the parenthesis, 2•-3 which = -6.
Second, distribute -6 (the one before the [5+2(-3)]).
It will look like 7x9-8+11-30-33
5 0
3 years ago
Read 2 more answers
If f(x) = c^2-2x and g(x) = 6x+4 , for which value of x
sp2606 [1]

hi        Step-by-step explanation:

4 0
3 years ago
Jamin wants to paint a wall in his bedroom. In order to know how much paint to buy, he first needs to know the approximate area.
Alekssandra [29.7K]

<u><em>Answer:</em></u>

Area of window = 3 ft²

Area to be painted = 45 ft²

<u><em>Explanation:</em></u>

To get the area to be painted, we will start by getting the area of the whole wall (including the window), then subtract from it the area of the window

<u>1- getting area of whole wall:</u>

From the figure, we can note that the length and width of the wall are given as 6 ft and 8 ft

Area of whole wall = length * width

Area of whole wall = 6 * 8 = 48 ft²

<u>2- getting area of window:</u>

Again, from the figure, we can note that the length and width of the window are 2 ft and 18 in (which is equivalent to 1.5 ft)

Area of window = length * width

Area of window = 2 * 1.5 = 3 ft²

<u>3- getting area to be painted:</u>

Area to be painted = area of whole wall - area of window

Area to be painted = 48 - 3 = 45 ft²

Hope this helps :)

5 0
3 years ago
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