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Kobotan [32]
3 years ago
14

ONE HUNDRED POINTS

Mathematics
2 answers:
Rudik [331]3 years ago
8 0

Answer:

I am literally dying from boredom because of quarantine

Step-by-step explanation:

fiasKO [112]3 years ago
5 0

dm on insta

skeet.in.the.sheets

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for a group experiment, your science class measured the fine-particulate concentration in the air at random places around campus
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Help I need some help please
sineoko [7]

Answer:

Option 4: \frac{4x-8}{-2x^2}

Step-by-step explanation:

A rational expression is undefined if the denominator (The bottom part of the fraction) is zero. If the denominator is zero, the fraction is automatically considered undefined, since there will never be an answer to the fraction.

To solve this question, all we need to do is replace x with 0 in the denominator, and see whether it becomes 0 or not.

For the steps I'll be writing below, I'll only be solving for the denominator since the value of the numerator does not matter at all in this question.

1. 3x - 3 --> 3(0) - 3 --> -3. The denominator is not zero, so it is defined.

2. 9x - 3 --> 9(0) - 3 --> -3. The denominator is not zero, so it is defined.

3. -x^2 + 1 --> -(0)^2 + 1 --> 1. The denominator is not zero, so it is defined.

4. -2x^2 --> -2(0)^2 --> 0. The denominator is zero, so it is undefined.

Since the 4th option was the only answer choice where the denominator became 0, that is our final answer.

(4x - 8)/(-2x^2) is undefined.

8 0
2 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
4 years ago
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vovikov84 [41]

Answer:

Step-by-step explanation:

b^{2*3} =b^{6}

6 0
3 years ago
Adrian made six free-throws Out of eight he attempted how many would you expect to make if you made 20 attempts
vovikov84 [41]
The answer will be 18
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