Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
Answer:
3n-1
Step-by-step explanation:
(4n+4) - (n+5)
i sperate it to be
4n-n and 4-5
so
3n-1 should be it
Answer: D) 0.733.
Step-by-step explanation:
Let C denotes the number of employees having college degree and S denote the number of employees are single.
We are given ,
Total = 600 , n(C)=400 , n(S)=100 , n(C∩S)=60
Then,
Now, the probability that an employee of the company is single or has a college degree is
Hence, the probability that an employee of the company is single or has a college degree is 0.733
The correct equation should look something like this:
y= -1x - 2
Consider the equation for a line:
y = mx + b,
Where ‘m’ is the slope
Where ‘b’ is the y-intercept.
From there you can plug in your known values for ‘m’ and ‘b’, and get the equation above. If you are still not convinced, I suggest you graph the function and observe its slope and y-intercept.
Hope this helps!
The subjects in the experiment are given as follows:
b) the two AP Statistics curricula.
<h3>What are the subjects of an experiment?</h3>
The subjects of an experiment are the hypotheses which are studied in the experiment.
For this problem, we are testing hypotheses involving two forms of the curriculum, hence the correct option is given by:
b) the two AP Statistics curricula.
More can be learned about the subjects of an experiment at brainly.com/question/2792045
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