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hjlf
3 years ago
12

which is a graph of f(x)=5x-2/x+2with any vertical or horizontal asympototes indicated by the dash lines?​

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

See attachment

Step-by-step explanation:

The given function is f(x)=\frac{5x-2}{x+2}.

This rational function has a vertical asymptote at where the denominator is zero.

The denominator x+2=0 when x=-2

There is vertical asymptote at x=-2

The horizontal asymptote for this rational function is given by the ratio of the leading coefficient of the numerator to the leading coefficient of the denominator.

y=\frac{5}{1}

The horizontal asymptote is y=5

The graph of this rational function is shown in the attachment  

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PLEASE HELP ASAP. I HAVE A VERY IMPORTANT TEST AND I NEED HELP
Katarina [22]

Answer:

i think 4 is b

Step-by-step explanation:

8 0
3 years ago
What should be done so that the expression will have a value of 10?<br><br> 12 - 2 + 2 2 ÷ 8
Liula [17]
Answer: 10
use (PEMDAS)
P parentheses ()
E exponents
M multiplication • , () , x
D division
A addition +
S subtraction -
Explanation:
There are no parentheses.
There are exponents.
The multiplication is the exponents.
There is division.
There is addition and subtraction.
-how to solve-
First, do 2 to the second power and get 4.
Next, do 12-2+4 divided by 8.
Next do multiplication: there’s no more.
Next do division: you can’t do 4 divided by 8 so instead, do 12-2 = 10 plus 8.
Hope this helps!
3 0
2 years ago
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

3 0
2 years ago
Read 2 more answers
A. 3s<br> B. s^2<br> C. s + 1<br> D. 2s + 1
Anna11 [10]
The answer is most likly to be B.
3 0
3 years ago
10 points!! Pls help with 5 and 6
marissa [1.9K]

Answer:

I only know number 5 so here it is

the solution for the left is: 2x6=12

the solution for the right is: 5x3+4x1=15+4=19

and the answers are: 1.12 . 2.19

5 0
2 years ago
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