Problem 16
<h3>Answer: i</h3>
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Work Shown:
The exponent 41 divided by 4 leads to
41/4 = 10 remainder 1
The "remainder 1" means that
i^(41) = i^1 = i
The reason why I divided by 4 is because the pattern shown below
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
repeats itself over and over. So this is a block of four items repeated forever.
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Problem 18
<h3>Answer: 1</h3>
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Work Shown:
Divide 3136 over 4 to get
3136/4 = 784 remainder 0
Therefore,
i^3136 = i^0 = 1
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Problem 20
<h3>Answer: i</h3>
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Work Shown:
Combine i^6*i^7 into i^13. We add the exponents here
Now divide by 4 to find the remainder
13/4 = 3 remainder 1
So, i^13 = i^1 = i
[1,2]
You have to look for the key words in order to find out how to solve; multiply divide etc.
Answer:
y=15
Step-by-step explanation:
-1/3(15)-6=-11
-5-6=-11
Y=<span>−33/<span>5
</span></span><span><span><span><span>53</span>y</span>+3</span>=<span>−8</span></span>Step 1: Subtract 3 from both sides.<span><span><span><span><span>53</span>y</span>+3</span>−3</span>=<span><span>−8</span>−3</span></span><span><span><span>53</span>y</span>=<span>−11</span></span>Step 2: Multiply both sides by 3/5.<span><span><span>(<span>35</span>)</span>*<span>(<span><span>53</span>y</span>)</span></span>=<span><span>(<span>35</span>)</span>*<span>(<span>−11</span>)</span></span></span><span>y=<span><span>−33</span><span>5</span></span></span>