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MAVERICK [17]
3 years ago
5

The product of two consecutive integers is equal to 14 more than 4 times the sum. This can be simplified to x²-7x-18=0. What are

the two integers?
Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

-1 and -2, or 9 and 10

Step-by-step explanation:

If x is the smaller integer:

x (x + 1) = 14 + 4 (x + x + 1)

x² + x = 14 + 4 (2x + 1)

x² + x = 14 + 8x + 4

x² − 7x − 18 = 0

Factor using AC method:

(x − 9) (x + 2) = 0

x = -2 or 9

x is the smaller integer, so the larger integers are -1 and 10.  Check each pair of solutions.

-1 and -2:

(-2) (-1) = 14 + 4 (-2 + -1)

2 = 14 + 4 (-3)

2 = 2

9 and 10:

(9) (10) = 14 + 4 (9 + 10)

90 = 14 + 4 (19)

90 = 90

Both solutions work.

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Answer:

S = {0,2,3,4}

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Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

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P(X=4) = \frac{12}{12^{4} }

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Mean, \mu = \sum xP(x)

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Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
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Ludmilka [50]

Answer:

Step-by-step explanation:

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5 0
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Answer:

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7x=2/7. x=2/7=1/7

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