log
(
5184
x
2
) i hope this helps because you didn't state if you wanted it simplified or not
Okay so.
2/5=24/60 (multiply 2/5 by 12)
2/3=40/60 (multiply 2/3 by 20)
1/4=15/60 (multiply 1/4 by 15)
Then,
Add 24/60 with 40/60 which is 64/60 after you get that you subtract by 15/60 and you get 49/60.
Hope this helps!^^
The <u>correct answer</u> is:
A) The medians are both between 10 and 14 emails.
Explanation:
The <u>mode </u>is the easiest measure to find of a data set.
The <u>mode </u>of a data set is the data value that appears the most often. In plot A, there are 3 dots at 10 and 3 dots at 15; this means the modes are 10 and 15.
In plot B, there are 3 dots at 5 and 3 dots at 15; this means the modes are 5 and 15.
They <u>do not have the same modes</u>.
The <u>median </u>of a data set is the middle value. There are 10 dots in each dot plot; this means the medians will each be between two data points.
For plot A, we can see that the middle value is between 10 and 15.
For plot B, we can see that the middle value is between 10 and 15.
This means that choice A is correct, the medians of both are between 10 and 14.
You want to isolate the x-term from the constant term, so you can subtract x/3 and add 10. This gives you
... 4/9x -10 -x/3 +10 > x/3 -12 -x/3 +10
... 1/9x > -2 . . . . . . collect terms
Now, you can multiply by 9 to see the condition on x.
... 9(1/9x) > -2(9)
... x > -18
On the x-y plane, the graph of this will be a dashed line at x=-18, and the half-plane to the right of that line will be shaded.
On a number line, there will be an open circle at x=-18, and the number line to the right of that circle will be marked (bold, colored, shaded, whatever).
Answer:
There is sufficient evidence at the 0.05 level
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
Step-by-step explanation:
percentage favoring construction of adjoining community = 47%
level = 0.05
To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
