Write an equation of a rational function that has a hole at 3, a vertical asymptote at -4 and a horizontal asymptote at 2

1 answer:

6 0

F(x)=2x(x-3)/(x+4)(x+3), Creation of the hole: have 3 as a solution for both numerator and denomenator
Formation of a vertical asymptote at -4: have the denominator equal to zero when plugging in -4 such that the denominator equals to zero,
horizontal asymptote: have the highest degree of numerator and denominator equal and the quotient of their coefficient equal to 2(ever wonder why there is an "x" in the numerator? It is to set the highest degree of the numerator and denominator equal to each other.
If you need more explanations, ask, glad to help.

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