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alex41 [277]
3 years ago
8

Write an equation of a rational function that has a hole at 3, a vertical asymptote at -4 and a horizontal asymptote at 2

Mathematics
1 answer:
Sauron [17]3 years ago
6 0
F(x)=2x(x-3)/(x+4)(x+3), Creation of the hole: have 3 as a solution for both numerator and denomenator 
                                     Formation of a vertical asymptote at -4: have the denominator equal to zero when plugging in -4 such that the denominator equals to zero, 
                                     horizontal asymptote: have the highest degree of numerator and denominator equal and the quotient of their coefficient equal to 2(ever wonder why there is an "x" in the numerator? It is to set the highest degree of the numerator and denominator equal to each other.
                     If you need more explanations, ask, glad to help.

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Find all the real values of X for which f(x)=0 <br><br> F(x)= x^3-x
Natalka [10]

Answer:

x=0,1,-1

Step-by-step explanation:

It factors as

X(x+1)(x-1)=0

5 0
3 years ago
Harvey is 3 times as old as Jane. The sum of their ages is 48 years. Find the age of each.
Marta_Voda [28]
Alright, let's answer this -

Half of 48 is 24... 

Half of 24 is 12...

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36 + 12 is equal to 48. =)
6 0
3 years ago
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Solve the equation for x <br> 3/10x-1/5=1
Vikki [24]

Answer:

x=4

Step-by-step explanation:

\frac{3}{10}x-\frac{1}{5}=1\\ \\\frac{3}{10}x=\frac{6}{5}  \\3x=12\\x=4

3 0
3 years ago
Please solve with explanation I’ve been asking all day (this is not a multiple choice question)
Anastaziya [24]

Answer:

a) SA = 522.9~cm^2

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Step-by-step explanation:

a)

For a cone,

SA = \pi r (L + r)

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We have r = 8 cm; h = 10 cm

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L = \sqrt{164~cm^2}

SA = (\pi)(8~cm)(\sqrt{164~cm^2} + 8~cm)

SA = 522.9~cm^2

b)

V_{cone} = \dfrac{1}{3}\pi r^2 h

V_{cone} = \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)

V_{cone} = 670.2~cm^3

c)

V_{cylinder} = \pi r^2 h

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V_{empty} = V_{cylinder} - V_{cone}

V_{empty} = \pi r^2 h - \dfrac{1}{3}\pi r^2 h

V_{empty} = (\pi)(8~cm)^2(10~cm) - \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)

V_{empty} = 1340.4~cm^3

3 0
3 years ago
Emma used 1/7 of a liter of milk to make 1/3 of a jug of tea. How much milk, in liters, is required to fill the jug?
fiasKO [112]

Answer:

Step-by-step explanation:

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Then  six times this must be a full jug....so

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6/7 liters of milk  required

i hope this helps you happy holidays let me know if you need more information

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