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Vesnalui [34]
3 years ago
11

Find the product of (3x²y²) (4xy³)²

Mathematics
2 answers:
allsm [11]3 years ago
6 0
(3x²y²)(4xy³)²
(3x²y²)(4xy³)(4xy³)
(3x²y²)(16x²y^6)
48x^4y^8
Elena-2011 [213]3 years ago
5 0
First, I would solve the second parenthesis.

(4xy^3)^2

Distribute

(4^2 x^2 y^6)

4 x 4 = 16

Now, combine like terms

3x^2 x 4x^2 = 12x^4

y^2 x y^6 = y^12

So, the answer would be 12x^4 y^12

Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong 
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What is the missing numerator? blank over five plus eighteen over twenty equals thirty over twenty 8 5 3 2
Oliga [24]

Given:

\dfrac{?}{5}+\dfrac{18}{20}=\dfrac{30}{20}

To find:

The missing value.

Solution:

Let x be the missing value.

We have,

\dfrac{x}{5}+\dfrac{18}{20}=\dfrac{30}{20}

\dfrac{x}{5}+\dfrac{9}{10}=\dfrac{3}{2}

Subtract \dfrac{9}{10} from both sides.

\dfrac{x}{5}=\dfrac{3}{2}-\dfrac{9}{10}

\dfrac{x}{5}=\dfrac{15-9}{10}

\dfrac{x}{5}=\dfrac{6}{10}

\dfrac{x}{5}=\dfrac{3}{5}

Multiplying both sides by 5, we get

x=3

So, the missing value is 3.

Therefore, the correct option is C.

8 0
3 years ago
Evaluate each expression x=-3,y=6,z=-4what is x+y+(-1)
Alex_Xolod [135]

substitute the numbers.

-3 + 6 - 1

= 2

8 0
3 years ago
Find out if the 3 positions are on the same line or not (3,2,0) (1, -1,2) (5,5, 2)
sattari [20]

Answer:

The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0),  B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

A-B=(3,2,0)-(1,-1,2)=(2,3,-2)

The equation of a line is:

p=p_0+rt

Where p is every singular point of the line, p_0 is a particular point of the line (any that we are sure that it is on the line), r is the director vector and t is the independent variable.

Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

p=p_0+(2,3,-2)t

Because there is a value for t that satisfies both A and B: If we do p_0=(3,2,0) and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\

If C is also in the same line, C must accomplish the equation: p=(3,2,0)+(2,3,-2)t, so:

C=(5,5,2)=(3,2,0)+(2,3,-2)t

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

5=3+2t\\5=2-3t\\2=-2t\\

You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

8 0
3 years ago
Simplify by combining like terms -17+2(6x-1)+5
earnstyle [38]

\huge\boxed{12x-14}

Start with the original expression.

-17+2(6x-1)+5

Use the Distributive Property — multiply 2 by both 6x and -1.

-17+12x-2+5

Combine the like terms — add up all the constants.

-14+12x

Reorder the terms.

\large\boxed{12x-14}

5 0
3 years ago
Read 2 more answers
10 ounces of orange juice for $2.40 0r 8 ounces for $2.08
denis-greek [22]

Answer:

8 for $2.08

Step-by-step explanation:

5 0
2 years ago
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