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Vesnalui [34]
3 years ago
11

Find the product of (3x²y²) (4xy³)²

Mathematics
2 answers:
allsm [11]3 years ago
6 0
(3x²y²)(4xy³)²
(3x²y²)(4xy³)(4xy³)
(3x²y²)(16x²y^6)
48x^4y^8
Elena-2011 [213]3 years ago
5 0
First, I would solve the second parenthesis.

(4xy^3)^2

Distribute

(4^2 x^2 y^6)

4 x 4 = 16

Now, combine like terms

3x^2 x 4x^2 = 12x^4

y^2 x y^6 = y^12

So, the answer would be 12x^4 y^12

Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong 
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2 years ago
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Firdavs [7]

Given:

A figure of a parallelogram.

The vertex angles are (12b+8)^\circ,(5b+2)^\circ,2a^\circ.

To find:

The values of a and b.

Solution:

We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.

(12b+8)^\circ+(5b+2)^\circ=180^\circ       (Supplementary angles)

(17b+10)^\circ=180^\circ

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Subtract 10 from both sides.

17b=180-10

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Divide both sides by 17.

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Now,

(5b+2)^\circ=(5(10)+2)^\circ

(5b+2)^\circ=(50+2)^\circ

(5b+2)^\circ=52^\circ

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(5b+2)^\circ+2a^\circ=180^\circ       (Supplementary angles)

52^\circ+2a^\circ=180^\circ

2a^\circ=180^\circ-52^\circ

2a^\circ=128^\circ

Divide both sides by 2.

a^\circ=\dfrac{128^\circ}{2}

a^\circ=64^\circ

a=64

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Answer:

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