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2 years ago

How many more stickers does maddie's have on her notebook than on meg's note book

Mathematics

1 answer:

Ksivusya [100]2 years ago

6 0

Depends on how many stickers each girl has.

You might be interested in

Which is equivalent toStartRoot 10 EndRoot Superscript three-fourths x ?

DENIUS [597]

Answer:

I THINK its the last one (8 root 10 to the power of 3x)

Step-by-step explanation:

A square root is the same thing as raising something to the 1/2. So the expression we have is (10^1/2)^3/4x.

Due to exponent rules we can multiply to get

10^3/8x which is the same thing as 10^3x/8

The 8 goes to the root and the 3x becomes the exponent

4 0

2 years ago

Pls give me the full answer

nikdorinn [45]

All of the Questions are solved on the images shown below. These images are from Microsoft Whiteboard that I created.

<h2>I'm in sixth grade, and don't know how to answer 2 and 5. So I'm only going to answer questions 1, 3 and 4. </h2>

really sorry about that

1. Answer = 90m²

3. Answer = 50in²

4. Answer = 108cm²

yup, this is how weird i am

I took the screen shot of answer 3 before 1 lol!

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so sorry I couldn't help on all problems

Always have more than 2 smiles so that you can share them to someone who doesn't have one! Me Happy! You Happy! EVERYONE HAPPY!

Thanks!

Have a great day!

7 0

1 year ago

Order from least to greatest. -1/5,1/7,-0.5,1/8

Ivenika [448]

There ya go, Hope, this helps

5 0

3 years ago

Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem

hammer [34]

Answer:

a) $A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) $||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) $A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

Step-by-step explanation:

a) considering the equation:

Minimize $x_{1}^{2} +2x_{2}x^{2} +3x_{3}^{2}+(x_{1} -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}$

$A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]$ (matrix A)

vector b

$b=\left[\begin{array}{ccc}0\\1\end{array}\right]$

b) If Pxn is matrix B and p-vector d, we have:

minimize $(-6x_{2}+4)^{2} +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}$

$Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]$

$\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]$

$Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1 \\x_{1}+8x_{2}-3 \end{array}\right] =1$

$||Ax-b||^{2} =(-bx_{2}+4)^{2} (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}$

c) minimize $2(-bx_{2}+4)^{2} +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2} +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2} -\sqrt{3})^{2} +(2x_{1} -16x_{2} -6)^{2}$

in matrix:

$A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]$

$x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]$

$b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]$

6 0

2 years ago

GUYS!!!!! HELP ME!!!!! Answer all the questions and I will give you brainliest!!!!!!!!!!

borishaifa [10]

Answer:

a=bxh is the answer

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers