0.2 x 40
=8
(change the percentage to a decimal)
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer: y+6x = -34
<em><u>Step-by-step explanation:</u></em>
y-2= -6(x+6) (<u><em>Ax+By=C is the goal)</em></u>
y-2= -6x-36 <u>(-6) x & (-6) 6</u>
y=-6x-34 (Add 2 to both sides)
<em>y+6x = -34 [Add 6x to both sides]</em>
Answer: I think your answer would be B
i hope it's right