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SashulF [63]
3 years ago
6

hey guys i need help on this lori is running in a marathon witch is 26.2 miles long .so far she has run one tenth of the maratho

n.how far has lori run?
Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0
This can be solved by multiplying 26.2 by 1/10 to get 2.62 You can also just move the decimal one to the left to get he same answer of 2.62 Lori has ran 2.62 miles
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Sides of a triangle are in the ratio of 12:17:25 and A perimeter of 540 cm. Find its area
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How to solve for 7/8 X c for c=8
zvonat [6]
Simple 7/8 is being multiplied by 8 or 8/1. When that is multiplied together 7/8*8/1, the 8's cancel each other out, and the answer is 7.
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what types of problems can be solved using the greatest common factor what types of problems can be solved using the last common
jonny [76]

Answer:

The greatest common factor is the biggest factor that divides two different numbers. For example, the greatest common factor of 6 and 8 is 2. The least common multiple is the smallest number that two numbers share as a multiple. For example, 12 is a the lowest common multiple of 3 and 4.

Step-by-step explanation:

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4 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

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You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
4 years ago
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lana [24]

Answer:

Step-by-step explanation:

Multiply 13*5 is 65

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