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3 years ago

10

A wallet that holds $25 contains the same number of $1 bills, $5 bills, and quarters. How many of each type of bill or coin does

the wallet contain?

2 answers:

Anastasy [175]3 years ago

3 0

<span>The wallet contains 4 $1 bills, 4 $5 bills, and 4 quarters.

$1 </span>× 4 = $4
$5 × 4 = $20
$0.25 × 4 = $1
$4 + $20 = $24, $24 + $1 = $25.

Alex17521 [72]3 years ago

3 0

It would hold 4 of each bill.

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Serggg [28]

Answer:

The solution is (4, 0)

Step-by-step explanation:

Using Linear combination method to solve:

$2d + e = 8\\d - e = 4\\$

Since "e" have the same coefficient in both equation with opposite operator; we will add.

$(2d + d) + (e - e) = (8 + 4)\\3d = 12\\$

Divide both side by coefficient of d which is 3

$\frac{3d}{3} = \frac{12}{3} \\d = 4\\$

Since d = 4; put 'd' into any of the equation to get 'e'

$2d + e = 8\\2(4) + e = 8\\8 + e = 8\\e = 8 - 8\\e = 0\\$

Therefore, the solution is (4, 0)

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