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iogann1982 [59]
3 years ago
5

Solve and graph the absolute value inequality: |4x + 1| ≤ 5.

Mathematics
1 answer:
Olegator [25]3 years ago
8 0
<span>|4x + 1| ≤ 5
Subtract 1 from both sides
|4x| <= 5
Divide both sides by 4
Final Answer: |x| <= 1.25

I can't graph it though.</span>
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The cost of a pizza at the pizza palace depends on the size of the pizza and the number of toppings. For a large pizza, the cost
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Answer:

The 2 represents that each toppings costs $2.

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F(x) = 4x + 7, g(x) = 3x^2 Find (f + g)(x)
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For the functions f(x) = 4x + 7 and g(x) = -9x + 11, find f(g(0)). For the functions f(x) = 3x2 - 7 and g(x) = -3x2 + 4, find f(g(2)). (Do NOT put commas in large numbers.)
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George bought socks for "$"300 and planned to sell them for $6 a pair. write an inequality to find the minimum number of socks h
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The inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

In the question, we are given that George bought socks for $300.

Therefore, George's total cost = $300.

We assume the number of pairs of socks George sells to be s.

The unit price per pair quoted by George = $6

Therefore, George's total sales = $6s.

We know that the profit over a transaction is given as the difference between sales and costs, that is,

The profit = The total sales - the total costs,

or, profit = 6s - 300.

In the question, we are required to make a profit of more than 210.

This can be shown by the inequality,

6s - 300 > 210.

Thus, the inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

Learn more about inequalities at

brainly.com/question/24372553

#SPJ4

5 0
2 years ago
the area of rectangle a is 11/12 square meters. the area of rectangle b is 8/12 square meters. how much larger is rectangle a?
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5 0
3 years ago
Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor
Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

If they work together they can do the entire prospectus in five hours

\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0
3 years ago
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