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3 years ago

Suppose the diameter of a circle is 6 units What is its circumference?

Mathematics

1 answer:

Kipish [7]3 years ago

6 0

Answer:

18.84 estimated, 6π exactly

Step-by-step explanation:

Hi!

<u>The formula for finding the circumference of a circle is 2πr:</u>

In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.

6 ÷ 2 = 3

So we have 2π × 3 to solve.

2π × 3 = 6π

We can estimate the circumference by multiplying by 3.14.

6 × 3.14 = 18.84

(actually multiplying by π gives 18.849... which is pretty close!)

Thus, the circumference is $\boxed{6\pi{\text{\:or\:18.84\:roughly}}}$ .

Hope this helps!

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Answer:

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3 years ago

What is the surface area of the figure? Use 3.14 for π.

fredd [130]

Answer:

Option 3

Step-by-step explanation:

We want to work out the surface-area

This is a cylinder and the formula for the surface area of a cylinder is :

2πrh+2πr^2

^ means to the power of

The radius is 15

The length is 18

2(3.14)(15)(18) + 2(3.14){15}^2

Part 1:

(6.28)(15)(18)

(6.28)(270)

1695.6

Part 2:

First, we do the exponents,

15^2 = 225

(6.28)(225)

1413

Part 3:

1695.6 + 1413 = 3108.6

Answer: 3108.6

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Which equation would you use to find how high the bird is flying

lisov135 [29]

Hi there! The fourth answer is correct.

In the picture we have to deal with facts:
1. The angle of 45°
2. The length of the opposite side
3. The length of the adjacent side.

Since we have to use the opposite and the adjacent side, we have to use the tangent of the angle. In a formula:
$\tan( \alpha ) = \frac{opposite}{adjecent}$

Filling in this formula, brings us to the following answer.
$\tan(45) = \frac{x}{1100}$

6 0

3 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago