Answer:
1. Construct a segment XY on the a sketch.
2. Elsewhere on the sketch, draw a line and create a point on the line . Label the point P.
3. Select point P and line segment XY. Construct circle by center and radius.
4. Select the circle and line, then construct point of intersection. Label one of the points of intersection point Q.
5. Select point P and point Q. Construct segment PQ.
6. Select the circle, line, and other point of intersection. Hide objects. Only segment XY and segment PQ should be visible on the sketch.
7. Try dragging point X. Segment PQ should lengthen and shorten as segment XY does.
Answer:
If it is a six-sided die then it has the probability of 1/6 or .16
Step-by-step explanation:
2789 dimensions because it’s simple u multiple them
Answer:
The probability of Javier volunteers for less than three a month is 25%
Step-by-step explanation:
According to the questions,
The probability of Javier to attend exactly 5 events :-
P ( x = 5 ) = 25% = 
The probability of Javier to attend exactly 4 events :-
P ( x = 4 ) = 
The probability of Javier to attend exactly 3 events :-
P ( x = 3 ) = 
The probability of Javier to attend exactly 2 events :-
P ( x = 2 ) = 
The probability of Javier to attend exactly 1 events :-
P ( x = 1 ) = 
The probability of Javier to attend no events :-
P ( x = 0 ) = 
Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).
P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )
P ( x < 3 ) =
=
=
= 0.25 = 25 %.
Answer:
Lydia
Step-by-step explanation: