Answer:
The first one is correct.
Step-by-step explanation:
-3.5 is inside of the shaded area of the line.
I hope this helps.
Given that G is the midpoint of FH, then:
FG=GH
hence;
14x+25=73-2x
solving for x we get:
14x+2x=73-25
16x=48
x=48/16
x=3
therefore the length FG=14x+25 will be:
14*3+25
=67
hence FH will be:
FH=67*2=134
Answer:
See below
Step-by-step explanation:
<u><em>Proof:</em></u>
<u><em>Statements </em></u> | <em><u>Reasons</u></em>
AD ≅ BC | Given
AD ║ BC | Given
AC ≅ AC | Reflexive Property
∠DAC ≅ ∠ACB | If 2 || lines are cut by a trans., the
| alternate interior ∠s are congruent.
ΔADC ≅ ΔBCA | S.A.S Postulate
BA ≅ DC | Corresponding sides of congruent Δs
So, quad. ABCD is a ║gm | If a quad. has its opposite sides
| congruent, the quad. is a parallelogram.
20 < 12 ⋅ <em>x</em> = 64
This is somewhat of a false equation though, due to the left side "20" is not less than the right side "12
", which means that the given statement is false.
So I switched it up and made the variable "12"
<u>12 < 20 ⋅ </u><u><em>x</em></u><u> = 64
</u>
12x - 20 = 64
12x = 64 + 20
12x = 84
12x⁄12 = 84⁄12
x = 7
____
I hope this helps, as always. I wish you the best of luck and have a nice day, friend..