You can work out c first. That's probably the key to the whole problem.
The adjacent side to a 60o angle is 1/2 the hypotenuse
The hypotenuse in this case = 4 Sqrt(3)
Then c = 1/2 (4 sqrt(3))
c = 2 sqrt(3) That means d is not true.
Next work out a.
a is in the same triangle as c and the hypotenuse.
a^2 + c^2 = hypotenuse^2
a = ??
c = 2 sqrt(3)
h = 4 sqrt(3)
a^2 + (2 sqrt(3))^2 = (4 sqrt(3))^2
(sqrt(3))^2 = 3
a^2 + 4 * 3 = 16 * 3
a^2 + 12 = 48
a^2 = 48 - 12
a^2 = 36
a = 6
Now we need to work out d
The side opposite and the side adjacent are equal when opposite a 45o angle in a right angle triangle
d = 6
The last thing to work out is be
a = 6
d = 6
c = ???
a^2 + d^2 = c^2
6^2 + 6^2 = c^2
c^2 = 72
c = sqrt(72)
c = sqrt(6*6*2)
c = 6 sqrt(2)
The answer should be B??? Check this out.
Answer:
x is 11 degree
Step-by-step explanation:
35+5x=90
5x=90-35
5x=55
x=11
this answer is found by linear equation method
Answer:
Step-by-step explanation:
They are all solved kind of the same way. If the vertex of the angle is outside of the circle, subtract the intercepted arcs and divide by 2
for 15) one arc is marked but you can figure out the other arc because there are 360 degrees in a circle 360 - 102 = 258. So the two arcs are 102 degrees and 258 degrees.
some of the problems you can set up the equation and solve.
17) 63 = {(360-x) - x} /2 multiply by 2
126 = {(360-x) - x} combine like terms
126 = 360 - 2x subtract 360
-234 = -2x divide by -2
117 = x
? = 117 degrees
good luck
Answer is choice C
"Dilate with a scale factor of two" means "multiply each coordinate by two"
A = (2,3) turns into A' = (4,6)
B = (3,5) turns into B' = (6,10)
C = (7,4) turns into C' = (14,8)
Side Note: this quick shortcut only works if the center of dilation is the origin (0,0). If the center of dilation isn't the origin, then you will have to do a translation (shifting) before you can use the trick, and then you'll have to shift back. The idea of the shifting is so that the center of dilation becomes the origin on a temporary basis. Because no mention is made of the reference center, it is assumed to be the origin by default.
