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Katarina [22]
2 years ago
6

Which of the following is an accurate statement? When the LOWER function is used in a SELECT clause, it will automatically store

the data in lower-case letters in the database table. When the LOWER function is used in a SELECT clause, the function stays in effect for the remainder of that user's session. When the LOWER function is used in a SELECT clause, the function only stays in effect for the duration of that SQL statement. none of the above
Computers and Technology
1 answer:
quester [9]2 years ago
5 0

Answer:

Hi there! The answer is C:

Explanation:

The scope of the LOWER function is limited to the select clause it is being used in. Outside of the select statement, the column will be returned as it is currently present in the database. Using the LOWER function will not automatically store data in lower case letters in the database tables. As an exercise, try creating a simple database table called "Employees" with columns "id" and "name". Then input a row using an insert statement with id as 1 and name as "BLAH". Try using the select statement with LOWER function and then without the LOWER statement.

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Which of the following occurs during data cleansing?
Diano4ka-milaya [45]

Answer:c)Clean redundant customer data

Explanation:Data cleansing/cleaning is the activity for the elimination of the data which is not required for further use, corrupt, unnecessary etc by detecting it. The data that is being cleared is categorized by levels like irrelevant  data, incorrect data, inaccurate data, redundant data etc.

The data is eliminated by the method of correcting , modifying, reducing unnecessary parts,deleting, etc.Thus, the correct option is option(C).

5 0
3 years ago
What data type would you use for a decimal number?* ​
Elan Coil [88]

Answer:

numeric

Explanation:

The decimal data type is an exact numeric data type defined by its precision (total number of digits) and scale (number of digits to the right of the decimal point).

I hope this answers your question.

3 0
2 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
2 years ago
Which security scanner runs in a web browser and doesn't require that you install a product before scanning
balandron [24]

Answer:

It’s OSI. also your question cut off lol

4 0
2 years ago
Given: int[][] values = new int[4][5] Using the statement above, write a nested loop to set values as follows: (3 pts) [0] [1] [
marshall27 [118]

Answer:

The question is a bit unclear. Are you asking how to add these values in this 2D array?

Explanation:

8 0
3 years ago
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