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stealth61 [152]
3 years ago
5

On what basis can you categorize the generations of computers?

Computers and Technology
1 answer:
murzikaleks [220]3 years ago
8 0

commercial computer age is from UNIVAC (Universal Automatic Computer)

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Name at least three real-life objects that are instances of each of the following classes:
DENIUS [597]

The three real-life objects that are instances of each of the following classes are given below:

a.<u> Song:</u>

The song Believe in yourself is an instance of song class

The song Where do broken hearts go is an instance of song class.

The song Ambition is an instance of song class

b. <u>CollegeCourse</u>

The College course Engineering is an instance of College course class

The College course Accounting is an instance of College course class

The College course Medicine is an instance of College course class

c. <u>Musician:</u>

The musician Rihanna is an instance of musician class.

The musician Sean Paul is an instance of musician class.

The musician Wyclef is an instance of musician class.

Real-life objects refer to the things that are characterized together as they share common qualities. The assignment simply wants you to name examples under the categories given.

Read related link on:

brainly.com/question/16699733

7 0
2 years ago
the manager of a xyz organisation is preparing the organizational chart which feature of MS Excel /he will use to do so? also wr
chubhunter [2.5K]

Answer:

Smart Art

Explanation:

The smart art feature in Microsoft excel allows for the creation of organizational chart on Microsoft excel. It readily allows for an hierarchical arrangement of an organization's personnel including the various departments on the system. The smartart allows the implementation of a graphical output which allows the display of an organization's personnel in order of hierarchy. To get started with smart art on excel, Clicking on the insert tab, the same are appears under illustrations. For an organizational chart, the Hierarchy smart art graphic type is selected and filled accordingly.

3 0
2 years ago
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
Shania has started a new job as an app developer. Her first task was to make an old app designed for Android available on other
quester [9]

Answer:

Option B is correct.

Explanation:

As such an application programmer, Shania recently began a new work. The first assignment was to create an earlier software available on certain devices, developed for Android.  

So, she using cross-platform software to compose application code that might convert the current android application code across various native versions to makes it much simpler and quicker for her job.

Other options are incorrect because they are not related to the following scenario.

4 0
3 years ago
Prove the following assertion: For every game tree, the utility obtained by MAX using minimax decisions against a suboptimal MIN
TiliK225 [7]

Answer:

From the given diagram, consider a MIN node whose children are terminal nodes, if MIN plays  

suboptimal. MIN will never be lower than the utility obtained playing against an optimal MIN  

MIN will always select a move having minimax utility greater than or equal to the move that is  

predicted by the minimax that is the MIN-played optimal value.  

Then the MIN node's value is increased to MAX. This is done by induction.  

One can do better than the minimax strategy, if the suboptimal play is predicted by MIN.

If MIN always falls for certain for certain kind of trap and losses, then setting up a trap guarantees a win.

Explanation:

See attached picture also.

5 0
3 years ago
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