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Marizza181 [45]
4 years ago
14

On a compass, due east is a 1/4 turn clockwise from due north. How many degrees are in a 1/4 turn?

Mathematics
2 answers:
Furkat [3]4 years ago
8 0
One full turn is 360 degrees. 1/4 of 360 degrees is 270
360-270=90 degrees. One fourth of a full turn is 90 degrees
vladimir2022 [97]4 years ago
4 0

Answer:

90^o

Step-by-step explanation:

We have been given that on a compass, due east is a 1/4 turn clockwise from due north.

Since we know that a compass is in form of a circle and the measure of degrees in a circle is 360 degrees.

To find the number of degrees in a one-fourth turn, we will divide 360 by 4.

\text{Number of degrees in a 1/4 turn of compass}=\frac{360^o}{4}

\text{Number of degrees in a 1/4 turn of compass}=90^o

Therefore, there are 90 degrees in a 1/4 turn of compass.

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81+6=h which equal 1 so 81+6+1
Ahat [919]

Answer:

81 + 6 + 1 = 88 if that's your question

Step-by-step explanation:

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3 years ago
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Solve using law of sines or law of cosines!
malfutka [58]

Answer:

Part 5) The length of the ski lift is 1.15\ miles

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

b=0.75\ miles

A=20\°

C=180\°-50\°=130\° ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

B=180\°-A-C

substitute

B=180\°-20\°-130\°=30\°

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute

\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}

c=\frac{0.75}{sin(30\°)}(sin(130\°))

c=1.15\ miles

Par 6)

see the attached figure with letters to better understand the problem

<u><em>Applying the law of sines in the right triangle BDC</em></u>

In the right  triangle BDC 20 degrees is the complement of 70 degrees

\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}

BC=(sin(70\°))\frac{x}{sin(20\°)} -----> equation A

<u><em>Applying the law of sines in the right triangle ABC</em></u>

In the right  triangle ABC 50 degrees is the complement of 40 degrees

\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}

BC=(sin(40\°))\frac{x+15}{sin(50\°)} -----> equation B

Equate equation A and equation B and solve for x

(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m

<u><em>Find the value of BC</em></u>

BC=(sin(70\°))\frac{6.6}{sin(20\°)}

BC=18.12\ m

therefore

The height of the tree is 18.12 m

5 0
4 years ago
What is the area of the shaded part of the figure if =14
aniked [119]

The area of the shaded part is: 42.14 ft² .

<h3>Area of Square</h3>

Area = s²

<h3>Area of Quarter Circle </h3>

Area = 1/4πr²

Thus:

Area of the shaded part of the figure = area of square - area of quarter circle

Area of shaded part = s² - 1/4πr²

s = 14 ft

r = 14 ft

Substitute

Area of shaded part = 14² - 1/4(3.14)(14²)

= 42.14 ft²

Therefore, the area of the shaded part is: 42.14 ft² .

Learn more about area of square on:

brainly.com/question/813881

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