Question

Speedy plumber charges $75 for a house call and 40 per hour for work done during the visit.Drains-r-us charges $35 for a house call and $60 per hour for work done during the visit.How many hours of work result in the same total cost for a house call from either company and how much is the cost?

Answer 1

Answer:

For 2 hours of work both the company's total charges would be same which is $155.

Step-by-step explanation:

Let the 'x' represents number of hours for work.

Also Let the 'y' represent the Total charge.

For Speedy Plumber Company:

Given:

Fixed charge = $75

Charge for each hour = $40

Amount of total charge is the sum of fixed charge and charge for each hour multiplied number of hours for work.

framing in equation form, we get;

$y =75+40x \ \ \ \ equation\ 1$

For Drains-r-us Company:

Given:

Fixed charge = $35

Charge of labor for each hour = $60

Amount of total charge is the sum of fixed charge and charge for each hour multiplied number of hours of work.

framing in equation form, we get;

$y =35+60x \ \ \ \ equation\ 2$

Now to find the hours of work result in the same total cost for a house call from either company, we will make both the equation equal we get;

$75+40x=35+60x$

Now we solve the equation,

Combining the like terms, we get;

$60x-40x=75-35\\\\20x=40$

Dividing both side by '20' using division property, we get;

$\frac{20x}{20}=\frac{40}{20}\\\\x=2$

Speedy Plumber Company charges after 2 hr = $75+40x =75+40\times2 =75+80 =\ 155$

Drains-r-us Company charges after 2 hr = $35+60x =35+60\times2 =35+120 =\ 155$

Hence For 2 hours of work both the company charges would be same which is $155.