The simplified form is 6x-6
First 1/5 is equivalent to 20% so to get 20% of both of them multiply by .2. so 400×.2=80 and 90×.2=18
Let
x-------------> amount added <span>to each side
</span>A-------------> area increased----------> 84 ft²
we know that
A=(10+x)*(5+x)=84-----------> 10*5+10*x+5*x+x²
50+15x+x²=84----------> x²+15x-34=0
<span>solving the second order equation
</span>x1=-17
x2=2
the answer is x=2 ft
<h3>Please markme as Brainliest .......</h3>
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
![x+y=5600...(1)](https://tex.z-dn.net/?f=x%2By%3D5600...%281%29)
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
![40x+20y=134000...(2)](https://tex.z-dn.net/?f=40x%2B20y%3D134000...%282%29)
Upon substituting equation (1) in equation (2), we will get:
![40x+20(5600-x)=134000](https://tex.z-dn.net/?f=40x%2B20%285600-x%29%3D134000)
![40x+112000-20x=134000](https://tex.z-dn.net/?f=40x%2B112000-20x%3D134000)
![20x+112000=134000](https://tex.z-dn.net/?f=20x%2B112000%3D134000)
![20x+112000-112000=134000-112000](https://tex.z-dn.net/?f=20x%2B112000-112000%3D134000-112000)
![20x=22000](https://tex.z-dn.net/?f=20x%3D22000)
![\frac{20x}{20}=\frac{22000}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B20x%7D%7B20%7D%3D%5Cfrac%7B22000%7D%7B20%7D)
![x=1100](https://tex.z-dn.net/?f=x%3D1100)
Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:
![y=5600-1100](https://tex.z-dn.net/?f=y%3D5600-1100)
![y=4500](https://tex.z-dn.net/?f=y%3D4500)
Therefore, 4500 end-zone tickets were sold.