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3 years ago

5

A 4x5 inch photo is enlarged by multiplying every dimension by 2 to form a similar 8x10 inch photo. What is the ratio of the per

imeter of the smaller rectangle to that of the larger?

1 answer:

iVinArrow [24]3 years ago

8 0

The first photo has a perimeter of 18
The second photo has a perimeter of 36

So, the ratio is 18:36 which simplifies to 1:2

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$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

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$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

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