Answer:
The answer to your question is 90 dB
Step-by-step explanation:
Data
I = 10⁻³
I⁰ = 10⁻¹²
Formula
Loudness = 10log ()
Process
1.- To solve this problem, just substitute the values in the equation and do the operations.
2.- Substitution
Loudness = 10 log
3.- Simplify
Loudness = 10log (1 x 10⁹)
Loudness = 10(9)
Loudness = 90
Answer:
critical value = 1.645
The 90% confidence interval = ( -22.62, -17.58)
Step-by-step explanation:
Given that:
the sample size = 178
the sample size = 226
the sample mean = 54.4
the sample mean = 74.5
population standard deviation = 18.58
population standard deviation = 9.52
level of significance ∝ = 1 - 0.90 = 0.10
The critical value for is 1.645
For the construction of our confidence interval, we use 90% since that is used to find the critical value.
∴
The margin of error =
2.52
The lower limit =
= ( 54.4-74.5) - (2.52)
= -20.1 - 2.52
= -22.62
The upper limit =
= ( 54.4-74.5) + (2.52)
= -20.1 + 2.52
= -17.58
The 90% confidence interval = ( -22.62, -17.58)
Answer:
y = 7x
Step-by-step explanation:
Given that y varies directly as x the the equation relating them is
y = kx ← k is the constant of variation
To find k use the points given
k = =
=
= 7
y = 7x ← equation representing the function