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3 years ago

Three out of every 10 students in Mr. Chan's class brings their lunch to school. Write this ratio as a percent

Mathematics

2 answers:

sergiy2304 [10]3 years ago

7 0

The ratio will be 3:10 you have turn 10 to 100 so you multiply it by 10. And multiply 10 by 3 will be 30/100

the answer is 30%

Katarina [22]3 years ago

4 0

The answer would be 30%.I think

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What is the length, width, and area

Temka [501]

Length: 6 Width: 2 Area: 12

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2 years ago

Marsha has some math exercises to do for homework. She did one half during study period and two thirds of those remaining while

Paha777 [63]

Answer: She has 1 5/6 exercises for homework.

Step-by-step explanation:

1/2 + 2/3 = 1 1/6

2 * 3 = 6 3 * 2 = 6

1 * 3 = 3 2 * 2 = 4

4 + 3/ 3 + 3

7/6 = 1 1/6

So, she finished 1 1/6 of her problems.

3 - 1 1/6 = 1 5/6

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3 years ago

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Which of the following is an equation of the line that crosses through (-3,4) and (3,6)?

Mama L [17]

Answer:

y=(1/3)x+5

Step-by-step explanation:

Slope-intercept: y=mx+b

m=((y2-y1)/(x2-x1)) = (6-4)/(3+3)= 2/6= (1/3)

y=(1/3)x+b

plug in one of the points (3,6)

6=(1/3)(3)+b

6=1+b 5=b

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2 years ago

A drawbridge rises at a rate of 3 2/3 feet per minute. The drawbridge rises to a height of 50 feet. How long does it take the dr

k0ka [10]

Answer: Third option.

Step-by-step explanation:

You know that the drawbridge rises at a rate of $3\ \frac{2}{3}$ feet per minute. This means that the drawbridge rises $3\ \frac{2}{3}$ in a minutes.

Convert from mixed fraction to decimal number:

$3\ \frac{2}{3}\ ft=(3+0.66)\ ft=3.6\ ft$

Since the drawbridge rises to a height of 50 feet, you need to apply this procedure in order to find the time the drawbridge takes to completely rise:

$time=\frac{(1\ min)(50\ ft)}{3.66\ ft}=13.6\ min$ or $13\ \frac{7}{11}\ min$

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3 years ago

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What is the seventh term of a sequence whose first term is 1 and whose common ratio is 3?

ikadub [295]

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=1\\
r=3\\
n=7
\end{cases}
\\\\\\
a_7=1\cdot 3^{7-1}\implies a_7=1\cdot 3^6\implies a_7=1\cdot 729\implies a_7=729$

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2 years ago