Hello!
To find the equation of a line parallel to y = 3x - 3 and passing through the point (4, 15), we need to know that if two lines are parallel, then their slopes are equivalent.
This means that we create a new equation in slope-intercept form, which includes the original slope, which is equal to 3.
In slope-intercept form, we need a y-intercept. So, we would substitute the given ordered pair into the new equation with the same slope and solve.
Remember that slope-intercept form is: y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the ordered pair (4, 15))
15 = 3(4) + b (simplify)
15 = 12 + b (subtract 12 from both sides)
3 = b
Therefore, the equation for the line parallel to the line y = 3x - 3, and passing through the point (4, 15) is y = 3x + 3.
Answer:
x = 16
Step-by-step explanation:
5 = 1/2(x) - 3
Add 3 to both sides.
8 = 1/2(x)
Rewrite for clarity.
1/2(x) = 8
x/2 = 8
Multiply both sides by 2.
x = 16.
Proof:
5 = 1/2(x) - 3
Substitute variable.
5 = 1/2(16) - 3
Multiply 1/2 and 16.
5 = 8 - 3
Subtract 3 from 8.
5 = 5
9 = 20 = 100 = 10 = -8 =
-24 = -18 = -16 = -38 =
Answer:
c.) <-1, 2> + <-2, -1>
Step-by-step explanation:
hope i helped
I think it's the second equation. I could be wrong but I think that's what it is
