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3 years ago

12

Explain why this algorithm works. In particular, Alice uses the numbers a = 3589 and 15619 as exponents. How are they related? S

imilarly, how are Bob’s exponents b = 4037 and 31883 related?

1 answer:

Paraphin [41]3 years ago

4 0

Answer:

The following attached is the solution. Hope it helps.

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Select the type of equations. <br><br> A)consistent <br> B)equivalent <br> C)inconsistent

Serga [27]

I think it might be c because theyre not equal

6 0

3 years ago

Read 2 more answers

20. Sketch the level curve of the function f(x, y) that contains the point (5,0).

PolarNik [594]

At the given point,

$f(5,0) = \dfrac1{\sqrt{5^2 + 0^2 - 9}} = \dfrac1{\sqrt{16}} = \dfrac14$

Then the level curve is

$\dfrac1{\sqrt{x^2 + y^2 - 9}} = \dfrac14 \\\\ \implies \sqrt{x^2 + y^2 - 9} = 4 \\\\ \implies x^2 + y^2 - 9 = 4^2 \\\\ \implies x^2 + y^2 = 25 = 5^2$

which is a circle centered at the origin with radius 5 - quite easy to sketch.

5 0

2 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Licemer1 [7]

Answer: Equivalent

Step-by-step explanation:

There is the same amount of red filling in the boxes in both.

5 0

3 years ago

Read 2 more answers

For question 21 ... I need the answer and explain how I got the answer !!!

maks197457 [2]

Answer:

27=3c-3(6-2c)

Open the brackets (multiply 6 and -2c by -3)

27=3c-18+6c

Add 3c and 6c

27=9c-18

Add 18 to both sides

45=9c

Divide by 9

c=5 (45/9)

now to check this just substitute c (5) into the equation

27=(3*5)-18+(6*5)

27=15-18+30

27=30-3

27=27

3 0

4 years ago

TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title

Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

$z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}$

$z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}$

Then

$\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}$

In trigonometric form, this is

$\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}$

8 0

3 years ago