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Marianna [84]
3 years ago
7

If all the edges of a prism are multiplied by 5, then the volume of the prism will be multiplied by?

Mathematics
2 answers:
sammy [17]3 years ago
6 0

Answer:

125

Step-by-step explanation:

Say prism A is a cube, and all the sides are x3, then the volume of prism A is .

nirvana33 [79]3 years ago
3 0

Answer:

125

Step-by-step explanation:

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Convert 1 /20 into a decimal and then into a percentage
DerKrebs [107]

Answer:

Decimal 1/20= .05

Percent 1/20= 5%

Step-by-step explanation:

7 0
3 years ago
2log(base 5)^(x-3)-log(base 5)^8= log(base 5)^2
Alja [10]

Answer:

x = 7

Step-by-step explanation:

2log_5(x-3)-log_58= log_52\\\\2log_5(x-3) =log_52+log_58\\\\2log_5(x-3) =log_5(2\times 8) \\\\2log_5(x-3) =log_516\\\\2log_5(x-3) =log_54^2 \\\\2log_5(x-3) =2 log_54 \\\\log_5(x-3) =log_54 \\\\x - 3 = 4\\\\x = 4+3\\\\\huge \orange { \boxed{x = 7}}

7 0
3 years ago
Find l.<br> 10 in.<br> l<br> b = [?] in.<br> 6 in.
stich3 [128]

Answer:

By applying Pythagoras theorem

Answer is √[109] inch

3 0
3 years ago
Logan and his brother plan to make spherical glass ornaments to decorate their living room. Logan decides to completely fill the
mixer [17]
For this case the first thing you should do is find the volume of the sphere.
 We have then:
 V = (4/3) * (pi) * (r ^ 3)
 Where,
 r: sphere's radius
 Substituting values we have:
 V = (4/3) * (3.14) * ((3/2) ^ 3)
 V = 14.13 in ^ 3
 Answer:
 
The amount of glitter required to completely fill one glass ornament is:
 
V = 14.13 in ^ 3
3 0
3 years ago
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 10 Allen's hummingb
ruslelena [56]

Answer: provided in the explanation segment

Step-by-step explanation:

(a). from the question, we can see that since that б is known, we can use standard normal, z.

we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?

⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;

x ± z * б / √m

which is

3.15 ± 1.28 * 0.32/√10

= 3.15 ± 0.1295 = 3.0205 or 3.2795

(b). normal distribution of weight (c) б is known

(c). option (a) and (e) are correct

(d).  from the question, let sample size be given as S

this gives';

1.28 * 0.32/√S = 0.15

√S = (1.28 * 0.32) / 0.15 = 2.73

S = 7.4529

cheers i hope this helps

6 0
3 years ago
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