Answer:
Answer is provided in the explanation section
Explanation:
Convert 8-bit 2’s complement form into 16-bit 2’s complement form.
First write value in binary then check for 8 th bit value. If it is positive the upper 8 bits will be zero otherwise will be 1s.
8-bit number Binary of number Insert 8 bits 16-bit number
0X94 1001-0100 1111-1111-1001-0100 0XFF94
0XFF 1111-1111 1111-1111-1111-1111 0XFFFF
0X23 0010-0011 0000-0000-0010-0011 0X0023
0XBC 1011-1100 1111-1111-1011-1100 0XFFBC
Which of the following 16-bit 2’s complement form can be shortened to 8-bits?
16-bit number 8-bit number
0X00BA 0XBA
0XFF94 MSB bits are not zero so we can’t truncate it to 8-bit No
0X0024 0X24
0XFF3C MSB bits are not zero so we can’t truncate it to 8-bit No
Answer:
Beta
Explanation:
Beta testing is a Quality Assurance process, where Developers and testers evaluate the quality of application experience from the point of view of the users, who are the most important targets of any software product.
Answer:
Management
Explanation:
Because Microsoft Access includes not only the software needed to create a database but also the software needed to create forms, reports, data dictionaries, and other capabilities, it is often referred to as a Database Management System (DBMS). A DBMS is used to maintain data consistency by managing the storage and retrieval of the data. Microsoft access can create and administer a database and has query components that are analogues to most DBMS.
I. 0xBED is a hexadecimal therefore we need to convert it to decimal first for ease of conversion. The calculation would just need B = 11, E = 14, and D = 13.
Then we just continuously divide the number by 3 and take the remainder in each step.
NUMBER REMAINDER
3053 2
1017 0
339 0
113 2
37 1
12 0
4 1
1 1
0
Finally we read the remainders from bottom to top to get the number's base 3 representation.
ANSWER: 11012002 (base 3)
ii. We can easily convert the decimal 3217 to binary by continuously dividing the number by 2 and taking the remainder in each step.
NUMBER REMAINDER
3217 1
1608 0
804 0
402 0
201 1
100 0
50 0
25 1
12 0
6 0
3 1
1 1
0
Then, we just read the remainder from bottom to top to get the decimal's binary representation.
ANSWER: 110010010001 (base 2)