If z is an even integer which of the following expressions must represent an odd integer?

1 answer:

8 0

There is no choice on your list that must represent an odd integer.

If 'z' is an even integer, then (z-1) and (z+1) must both be odd integers.

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Can someone help me

Lemur [1.5K]

Multiplying fractions is just multiplying the numerators together and the denominators together.

$\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}$

$\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}$

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

$\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}$

Now just compare the numerators to see which one is bigger.

$\sf\dfrac{3}{21}>\dfrac{2}{21}$ therefore, $\sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}$

5 0

3 years ago

What is 3(x+3)+7x= ?

dusya [7]

The answer is 6x+7x there is no answer without the value of c

3 0

3 years ago

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Four more than double a number is 100 what is the answer?

algol13

Answer:

the number would be 48 i think

Step-by-step explanation:

48 + 48 = 96

96 + 4 = 100

7 0

3 years ago

Please I need this quick!!! 15 points

professor190 [17]

Let the number be n.

Then:

n^2 + (1/n)^2 = 82/9; find n. Find the LCD; it is 9n^2.

Mult all 3 terms by 9n^2:
82*9n^2
9n^4 + 9 = (82/9)(9n^2) => 9n^4 + 9 = ------------
   9
Then 9n^4 - 82n^2 + 9 = 0

I used my graphing calculator to find that n = 3.

Let's check: is 3^2 + (1/3)^2 = 82/9?
Is 9 + 1/9 = 82/9?
Is 81 + 1 = 82? YES. So, n=3 is a solution.

7 0

3 years ago

What is the value of<br> 4x3 + 4x when x = 4?

svetlana [45]

Answer:

yes this is the right answer is 4X

8 0

2 years ago

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