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Salsk061 [2.6K]
3 years ago
13

Find the equation of the axis of symmetry

Mathematics
1 answer:
Over [174]3 years ago
7 0
There is no answer for axis of symmetry
But I have the answer for (x-intercept) X= -4/5 (y-intercept) F(0)=16
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40% of = 8 please help
guajiro [1.7K]

Answer:

3.2

Step-by-step explanation:

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3 years ago
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Choose an equation of a line through the point (-4, -2) parallel to y=14x−3.
Likurg_2 [28]

Answer:

  1. I think im gonna pass this onee maybe
3 0
3 years ago
Write the following expression using symbolic language.
Ad libitum [116K]

Answer:

<h3>              1)   7x - 5 </h3><h3>              2)   9y - 18 </h3><h3>              3)   0.5n + 4n </h3><h3>              4)  2(w³+23)</h3><h3> Step-by-step explanation:</h3>

1)

The product of seven and a number x:   7·x = 7x

<u>Five less than the product of seven and a number x:</u>

<h3>7x - 5 </h3>

2)

nine times a number y:  9·y = 9y

<u>The difference of nine times a number y and eighteen:</u>

<h3>9y - 18 </h3>

3)

half a number n:   0.5n

four times the number:   4·n = 4n

<u>Half a number n increased by four times the number:</u>

<h3>0.5n + 4n </h3>

4)

a number w cubed:  w³

the sum of a number w cubed and twenty-three:  w³+23

<u>Twice the sum of a number w cubed and twenty-three:</u>

<h3>2(w³+23)</h3>

5 0
3 years ago
Who should fill out the W-2 form?
Flauer [41]
I think B is the answer. I am not sure
8 0
4 years ago
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Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
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