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Lina20 [59]
3 years ago
11

Your class has 26 students, which represents 5% of your school's enrollment. Your friend uses the proportion 5/100 =n/26 to find

the number of students in your school . Explain your friend's error? Can you guys please help me on this problem. By the way the / is a fraction. Thanks!
Mathematics
1 answer:
dedylja [7]3 years ago
7 0
26 is a part of the whole. the proportion should be set up:

(26/x) = (5/100) It's the overall enrollment that is being asked.

If you also need to solve: Cross multiply, 26(100) = 5x, 2600 = 5x, divide both sides by 5, 520 is the enrollment
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Change 04:35 to 12 hours clock time​
mote1985 [20]

Answer:

4:35 am

Step-by-step explanation:

change 04:35 to 12 hours clock time

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2 years ago
12/21 in its simplest form
UNO [17]
12/21 in its simplest form is 4/7.

To find this out we need to divide the numerator and denominator by the GCF of 12 and 21 which is 3.

12/21

12 ÷ 3 = 4
21 ÷ 3 = 7
4/7

12/21 in its simplest form is 4/7.

12/21 = 4/7
5 0
3 years ago
Read 2 more answers
62 is 90.5% of what number?
Reptile [31]
68.5. You take 62 and divide it by the percentage as a decimal, .905. 62 / .905 = 68.5.
6 0
3 years ago
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Make a table of values for the function rule. then graph the function. y=-x²+4​
lakkis [162]

Answer:

check the attached picture

Step-by-step explanation:

Given function is y=-x^2+4.

Now we need to make a table of values for the function rule then graph the function.

We are free to plug any values of x like -3,-2,-1,0,1,2,3,... etc becaues domain of polynomial function is all real numbers.

Let's plug x=1 into given function to find the y-value

y=-x^2+4

y=-(1)^2+4

y=-1+4

y=3

Hence the first point is (1,3).

Same way we can find few more points to complete the table then graph those points and connect them to get the final graph.

x y

-2 8

-1 5

0 4

1 5

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5 0
3 years ago
Part A: Factor x2y2 + 6xy2 + 8y2. Show your work. (4 points) Part B: Factor x2 + 8x + 16. Show your work. (3 points) Part C: Fac
skad [1K]

Answer:

Part A : y²(x + 2)(x + 4)

Part B: (x + 4) (x + 4)

Part C: (x + 4) (x - 4)

Step-by-step explanation:

Part A: Factor x²y²+ 6xy²+ 8y²

x²y²+ 6xy²+ 8y²

y² is very common across the quadratic equation , hence

= y² (x² + 6x + 8)

= (y²) (x² + 6x + 8)

= (y²) (x² + 2x +4x + 8)

= (y²) (x² + 2x)+(4x + 8)

= (y²) (x(x + 2)+ 4(x + 2))

= y²(x+2)(x+4)

Part B: Factor x² + 8x + 16

x² + 8x + 16

= x² + 4x + 4x + 16

= (x² + 4x) + (4x + 16)

= x( x + 4) + 4(x + 4)

= (x + 4) (x + 4)

Part C: Factor x² − 16

= x² − 16

= x² + 0x − 16

= x² + 4x - 4x - 16

= (x² + 4x) - (4x - 16)

= x (x + 4) - 4(x + 4)

= (x + 4) (x - 4)

6 0
3 years ago
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