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anygoal [31]
3 years ago
9

At the movie theatre, child admission is S5.20 and adult admission is $8.30. On Tuesday, 156 tickets were sold for a total sales

of S1087.10. How many adult
tickets were sold that day?
Mathematics
1 answer:
Annette [7]3 years ago
8 0

Answer:

So, 89 Adult tickets were sold.

Step-by-step explanation:

So, we first name our variables, say, a for number of adult tickets, and c for child tickets.

Then we write our system of equations, first the total $ sale:

5.2c + 8.3a = 1087.10

Then we write the 2nd equation, the total number of tickets:

c + a = 156

Now, we can solve the system:

We do have different methods, let's to by subsitution.

make some change to the 2nd equation, to make c the subject: c = 156 - a

Now we plug that into the 1st equation:

5.2(156 - a) + 8.3a = 1087.10

811.2 - 5.2a + 8.3a = 1087.10

811.2 + 3.1a = 1087.10

3.1a = 275.9

a = 89

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11. The formula to find the AREA of a triangle is A = 1/2bh<br> True<br> False
Vera_Pavlovna [14]

Answer:

True

Step-by-step explanation:

The formula for the area of a triangle is:

area=(base x height)/2

7 0
3 years ago
The second of two numbers is 3 less than twice the first. Their sum is 36. Find the numbers.
swat32
<span>The first number = x
The </span>second number = 2x-3

x + 2x-3 = 36
3x = 36+3
3x = 39
x = 39/3
x = 13

The first number = x = 13
The second number = 2x-3 = 2*13 - 3 = 26 - 3 = 23
7 0
3 years ago
...........................
Arisa [49]

Answer:

B) b√a

Step-by-step explanation:

b√a

8 0
3 years ago
Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
3 years ago
Need help on these. Don't answer if you don't know. I'm looking at YOU, bmdaniel1
andre [41]

Answer:

use m a t h w a y

really easy to use

works for all algebraic equations

Step-by-step explanation:

7 0
3 years ago
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