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grandymaker [24]
3 years ago
14

Suppose that 12 people enter an elevator on the 1st floor of a 24 floor building. Assume that all 12 independently pick a floor

(above the first) randomly to get off on. What is the expected number offloors no one gets off on?
Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

∑E(x_{i}) = 13.49167 floors

Step-by-step explanation:

The expected number of floors no one get off = ∑E(x_{i}) where i is from 0 to 23

and E(x_{i}) = ∑x_{i}P(x_{i})

here x_{i} is the indicator of floor where no one gets off, its value is 0 when  atleast one person get off on its floor and 1 when when no one gets off.

Now,

P(x_{i}=1) = (22/23)¹²

P(x_{i}=0) = [1-(22/23)¹²]

Now,

E(x_{i}) = ∑x_{i}P(x_{i}) = 0* [1-(22/23)¹²] + 1*(22/23)¹² =0.586594704

For total number of floors where no one gets off

∑E(x_{i}) = E(x₁)+E(x₂)+E(x₃)........................+E(x₂₃)

∑E(x_{i}) = 23*0.586594704

∑E(x_{i}) = 13.49167 floors

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Then we have the multiplication:

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Let's distribute the multiplication:

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Then the list of six multiplications involved in solving this problem are:

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Now we add all of those and get:

325*89.1 = 24,400 + 2,700 + 30 + 2,000 +  225 + 2.5 = 28,957.5

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