<u>Part A</u>
<u />
<u>Part B</u>
The vertex of the graph will be a maximum because the leading coefficient is negative.
The x coordinate of the vertex is 
.
When x=15/8, 
.
So, the vertex has coordinates 
<u>Part C</u>
Plot the two x-intercepts and the vertex and then draw a curve in the shape of a parabola passing through them.
The graph is in the attached image.
Answer:
Step-by-step explanation:
Note that this function is not defined at x = 0; it does have a vertical asymptote which is the line x = 0, as well as a horiz. asymptote which is the line y = 0. This function is odd because the power of x is -1 (a negative odd number). Half the graph appears in Quadrant I: (1, 1), (2, 1/2), (3, 1/3), etc.
The other half is the reflection of the Quadrant I part in the origin, and this is because the function is odd.
Answer:
Option c) Transitivity
Step-by-step explanation:
We are given the following information in the question:
If A exceeds B in some property and B exceeds C, then A must also exceed C.
We have to define the property shown by A,B and C.
Transitivity:
- It is a mathematical property which states that between three numbers if first and second share the property, second and third share the property, then according to transitive property, the property holds between first and third as well.
Thus, A, B and C here shows the transitive property.
The correct answer is
Option c) Transitivity
I'd stay this expression is already in standard form, although you could rewrite it as -(<span>-4x^2-12x+1).
You could rewrite </span><span>-4x^2-12x+1 by completing the square:
-4(x^2 + 3x ) +1 becomes
-4(x^2 + 3x + [3/2]^2 ) - [3/2]^2 + 1, or
-4(x + 3/2)^2 + 1 - 9/4, or
-4(x+3)^2 -5/4 (final form) The graph would be that of a parabola with vertex at (-3, -5/4). This parabola would open down and would be vertically stretched by a factor of 4.</span>
