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jonny [76]
3 years ago
14

What type of number is -7.89? Select all that apply

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
The answer to this question is INTEGER
Morgarella [4.7K]3 years ago
6 0
Actually it’s only rational because it’s -7.89 if it were -7 than it would be integers and rational
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A high school soccer goalie blocked the ball from going into the goal 4 out of 5 times. If the ball kicked toward the goal 25 ti
miskamm [114]
We can use a ratio expression to find the answer to this problem.

Set up the ratio.
4/5 = x/25
Multiply both sides by 25.
100/5 = x
Divide by 5.
20 = x
This means out of 25 times the ball is kicked toward the goal, the goalie will block it 20 times.
4 0
3 years ago
Read 2 more answers
What is the solution to the inequality |2n+5| > 1 ?
Serhud [2]

Answer:

n > -2                 or      n < -3

Step-by-step explanation:

|2n+5| > 1

We have two solutions one positive and one negative.  Remember to flip the inequality symbol for the negative

2n+5 > 1         or 2n+5 < -1

Subtract 5 from each side

2n+5-5 > 1-5         2n+5 -5 < -1 -5

2n >-4                    2n < -6

Divide by 2

2n/2 > -4/2             2n/2 < -6/2

n > -2                 or       n < -3

4 0
3 years ago
FIND THE VOLUME OF THE PRISM
ki77a [65]

Answer:

volume of prism is 157.464

6 0
3 years ago
Plz help asap. i beg
iren [92.7K]
D is integer and rest r rational I guess
3 0
3 years ago
Read 2 more answers
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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