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balandron [24]
2 years ago
11

Can you guys help and put these in order?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0
-3, -2.5, -3/4, 1/4, 3.1, 16/5, 6. I can’t see the other numbers, so it’s just these
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When solving secθ=−4.2 for 180°≤θ≤360°, how many possible answers are there?
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Solve the exponential equation: 6x-3 = 216x-3
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Step-by-step explanation:

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According to a Pew Research Center study, in May 2011, 35% of all American adults had a smart phone (one which the user can use
taurus [48]

Answer:

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

p_v =P(z>1.82)=0.034  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis

And the best conclusion would be:

There is enough evidence to show that more than 35% of community college students own a smart phone (Pvalue = 0.034).

And for the second case the correct system of hypothesis is:

H0: p = 0.078; Ha: p > 0.078

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=\frac{120}{300}=0.4 estimated proportion of college students that have a smart phone

p_o=0.35 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is >0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>1.82)=0.034  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis

And the best conclusion would be:

There is enough evidence to show that more than 35% of community college students own a smart phone (Pvalue = 0.034).

And for the second case the correct system of hypothesis is:

H0: p = 0.078; Ha: p > 0.078

4 0
3 years ago
Find the height of the tree.
Burka [1]

Answer:

16 ft

Step-by-step explanation:

We start by converting 1yd to ft,

1yd = 3ft

So in the smaller triangle, we have 3ft, 4.5ft. Using Sine, Cos, and Tan rule. We know that

TanΦ = opposite / adjacent

TanΦ = 3ft / 4.5ft

TanΦ = 0.667

Φ = Tan^-1 0.6

Φ = 33.69

This means that the angle of elevation is 33.69°

Using this angle, and the same tan rule again, we gave

Tan 33.69 = opp/24

0.667 = opp/24

opp = 24 * 0.667

opp = 16 ft

5 0
3 years ago
Read 2 more answers
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