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Novay_Z [31]
3 years ago
8

Carbon and oxygen are helpful in metabolic studies because: Select one: a. They are inexpensive elements b. They are incorporate

d into organic material and common found in living things c. Scientists know a lot about these two elements d. They are plentiful in nature
Biology
1 answer:
lord [1]3 years ago
4 0
B. They are incorporated into organic material and common found in living things.<span />
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A recipe for a cake calls for both liquid and dry ingredients. If you are following the recipe, how will the order in which you
Nookie1986 [14]

It will have no effect because the order in which ingredients are mixed will not change the fact that matter cannot be created nor destroyed.

<h3>Effect occurs on mass</h3>

The order in which we add the ingredients do not affect the mass of the batter because the order in which ingredients are mixed will not change the fact that matter cannot be created nor destroyed.

The mass of the batter remains the same due to the incorporation of same quantity of ingredients so we can conclude that option A is the right answer for this question.

Learn more about matter here: brainly.com/question/3998772

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What is the study of geology an meterology
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Geology is the study of the earth and meteorology is the study of the earths atmosphere
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4 years ago
PLZ HELP ME I WILL MARK YOU AS BRAINLIEST
attashe74 [19]
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5 0
4 years ago
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Under anaerobic conditions, such as intense exercise, pyruvate is converted to ____________ . This 3-carbon molecule travels thr
stiv31 [10]

Answer:

Under anaerobic conditions, such as intense exercise, pyruvate is converted to <u>lactate.</u> This 3-carbon molecule travels through the blood to the liver, where it can be converted to glucose by the <u>cori cycle.</u>

Under aerobic  conditions, pyruvate enters the mitochondrion, where it is converted to <u>acetyle CoA . </u>This 2-carbon molecule goes on to participate in a series of oxidative reactions called the <u>Citric acid cycle.</u>

Explanation:

In the question ,among the given 6 options ,the simplest way to find the answer can be ,to find either the option is aerobic (presence of free oxygen ) or anaerobic (lack of  free oxygen). Among the options , glucose is an incorrect option as it is a carbohydrate and used in respiration process .In aerobic process ,the glucose can be break down but in anaerobic ,it can only be used.

Other option is ATP- ATP is the energy source of the cell and used for storing energy or reactions of the cell,thus this option do not belong to the given question.

thus its clear the rest four options are the answer .

among four two options belong to aerobic and the rest two are anaerobic.

<u>Under anaerobic conditions-</u>

The pyruvate is converted into lactate because under the absence of oxygen only the NAD+ can be regenerated, thus further can allow glycolysis.

The cori cycle is also called lactic acidic cycle, thus this cycle is a metabollic pathway produced by anaerobic glycolysis (which takes place by regeneration of NAD+)transporting the molecules from blood to liver and  further converting to glucose

<u>Under aerobic conditions,-</u>

The pyruvate is converted into <u>Acetyle CoA </u>so as to further produce <u>citric acid  </u>and then citric acidic cycle. Thus Acetyle CoA forms more ATP which help in the regeneration of NAD+ and production of citric acid cycle takes place.

<em>HENCE , The correct options are - </em><u>lactate </u>  <u>cori </u>  <u>acetyle CoA </u>  <u>citric acid.</u>

7 0
4 years ago
In cats the allele for short hair is dominant over the allele for long hair. A short haired male and long haired female have kit
SCORPION-xisa [38]

Answer:

Genotype of parents:                  Ss     x     ss

Genotype of offsprings:                  Ss    ss

Expected ratio of short to long:      2  :   2 = 1 :  1

The actual ratio in this problem is Eight kittens have short hair and 3 have long hair: 8 : 3

Explanation:

In cats the allele for short hair is dominant over the allele for long hair. (SS or Ss for short hair; ss for long hair).

A short haired male and long haired female have kittens. Eight kittens have short hair and 3 have long hair.

For the parents to have been able to produce long haired offsprings, it means both parents possess one copy each of the recessive traits. Thus we have

Phenotype of parent: A short haired male and long haired female

Genotype of parents:                  Ss     x     ss

Genotype of offsprings:                  Ss    ss

Expected ratio of short to long:      2  :   2 = 1 :  1

The actual ratio in this problem is Eight kittens have short hair and 3 have long hair: 8 : 3

4 0
3 years ago
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