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Ksivusya [100]
3 years ago
7

Determine the slope of a line that is perpendicular to the line y = -2x + 7

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

C)

Step-by-step explanation:

Perpendicular means negative reciprocal of the current slope.

And the negative reciprocal of -2 is 1/2.

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If a = 4 units, b = 7 units, c = 8 units, d = 11 units, and e = 5 units, what is the volume of the composite figure?
s2008m [1.1K]

Answer:

hey brother answer for your tricky question is point d286 cubic meter

hope it may help you brother

4 0
3 years ago
Proving a Quadrilateral Is a Parallelogram
Schach [20]

Answer: a. yes, one pair of opposite sides could measure 10in., and the other pair could measure 13 in.

Step-by-step explanation: i just took it

8 0
3 years ago
Solve for x in the equation x^2+4x-4=8
quester [9]
I will get you started.

x^2+4x-4 = 8

x^2 + 4x - 4 - 8 = 0

x^2 + 4x - 12 = 0

You must now use the quadratic formula.

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Take it from here.
8 0
3 years ago
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
Why does a radical function with an even index only appear on one sode of the x-axis while a radical woth an odd index appears o
Vladimir79 [104]

Consider the equation y = x^2. No matter what x happens to be, the result y will never be negative even if x is negative. Example: x = -3 leads to y = x^2 = (-3)^2 = 9 which is positive.

Since y is never negative, this means the inverse x = sqrt(y) has the right hand side never be negative. The entire curve of sqrt(x) is above the x axis except for the x intercept of course. Put another way, we cannot plug in a negative input into the square root function for this reason. This similar idea applies to any even index such as fourth roots or sixth roots.

Meanwhile, odd roots such as a cube root has its range extend from negative infinity to positive infinity. Why? Because y = x^3 can have a negative output. Going back to x = -3 we get y = x^3 = (-3)^3 = -27. So we can plug a negative value into the cube root to get some negative output. We can get any output we want, negative or positive. So the range of any radical with an odd index is effectively the set of all real numbers. Visually this produces graphs that have parts on both sides of the x axis.

3 0
3 years ago
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