(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when
and
, and because the velocity function is continuous, you need only check the sign of
for values on the intervals (0, 3) and (3, 6).
We have, for instance
and
, which means the particle is moving the positive direction for
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

which follows from the definition of absolute value. In particular, if
is negative, then
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so
is the derivative of
:

Compute the acceleration at
seconds:

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)
Answer:2.0736
Step-by-step explanation:
Answer:
270 ÷ 30 = 9
Step-by-step explanation:
9x3=27
90x3 = 270
27 ÷ 3 = 9
270 ÷ 30 = 9
90 x 3 = 270
30 x 9 = 270
Answer:
729015430.40641995 = 729015430.41
Step-by-step explanation:
Since the 3 decimal place is 6, you round up. If you round up for 0 you get 1. Therefore your answer is 729015430.41.