the 5th hour there would be 4 puppies available for adoption
The 6th hour would have 2 puppies available for adoption
these answers are only correct if the ratio stays the same
Answer:
parent function is the simplest form of the type of function given.
The transformation from the first equation to the second one can be found by finding , , and for each equation.
Find , , and for .
Find , , and for .
The horizontal shift depends on the value of . The horizontal shift is described as:
- The graph is shifted to the left units.
- The graph is shifted to the right units.
Horizontal Shift: None
The vertical shift depends on the value of . The vertical shift is described as:
- The graph is shifted up units.
- The graph is shifted down units.
Vertical Shift: None
The sign of describes the reflection across the x-
The cost of 1 vanilla ice cream and 1 strawberry ice cream should total to $31. Since you only bought one of each flavor, you simply have to add their unit prices.
Cost for 1 carton of strawberry ice cream + Cost for 1 carton of vanilla ice cream = Total Cost
Total Cost = s + v --> this is the general equation
Since s = 1.5 + v, the modified equation would be
Total Cost = 1.5 + v + v
Total Cost = 1.5 + 2v
Since it's isosceles, ∠ABC = (180-30) / 2 = 75
Answer:
p > 5 and p <-8
Step-by-step explanation:
To solve this, you first need to isolate p.
First add 6 on both sides of the equation:

Then subtract 3 from both sides of the equation.

The divide both sides by 2.

Another solution is possible because of the absolute value.
If 
Then 
<em>Thus we can solve the second solution:</em>


Isolate P again by subtracting both sides by 3


Then divide both sides by 2:

