Because there are 4 students who passed in all subjects, we can say that only 2 students passed in English and Mathematics only, only 3 students passed in Mathematics and Science only, and no one passed in English and Science only.
Given that we have deduced the number of students who passed in two subjects, we can now solve for the number of students who passed only one subject.
English = 15 - (4 + 2 + 0) = 9
Mathematics = 12 - (4 + 3 + 2) = 3
Science = 8 - (4 + 3 + 0) = 1
1. In English but not in Science,
9 + 2 = 11
2. In Mathematics and Science but not in English
3 + 3 + 1 = 7
3. In Mathematics only
= 3
3. More than one subject only
3 + 4 + 2 + 9 = 18
It will really be helpful if you draw yourself a Venn Diagram for this item.
Umm what’s the question??
Answer:
10010
Step-by-step explanation:
So 
gives us:
-----------------------------------------------------
Combine like terms:
We aren't allowed to have a coefficient bigger than 1.
I'm going to replace 
with 1 and 
with 
:
I want a number:
Combine like terms:
:
Combine like terms:
We can rewrite the first term by law of exponents:
So the binary form is:
Maybe you like this way more:
Keep in mind 1+1=10 and that 1+1+1=11:
Setup:
1 0 1 1
+ 1 1 1
------------------------------
(1) (1) (1)
1 0 1 1
+ 1 1 1
------------------------------
1 0 0 1 0
I had to do some carry over with my 1+1=10 and 1+1+1=11.
19.1 should be your answer
To do this subtract 2 from each side of the equation to get y = -5, so the value of y in this is -5. Hope this helps!
