A farmer has 100 m of fencing to enclose a rectangular pen.
2 answers:
A(w) = 50w-w^2
rewrite it as y = -w^2 +50w
using quadratic formula y = ax^2 +bx +c
a would equal -1, b = 50 and c = 0
find the axis of symmetry using x = -b/2(a)
so x = -50 / 2(-1) = -50/-2 = 25
so the width = 25 m
the greatest area is a square, so area = 25^2 = 625 square meters
Answer:
The greatest rectangular area that the farmer can enclose with 100 m of fencing is 625m2.
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