1. A scuba diver was exploring a reef 32.12 m below sea level. The diver ascended to the surface at a rate of 8.8 m/min.

Mathematics

2 answers:

Cerrena [4.2K]4 years ago

8 0

A scuba diver was exploring a reef 32.12 m below sea level. The diver ascended to the surface at a rate of 8.8 m/min.

a. using the formula d = rt, so 32.12 m = 8.8m/min (t)

b. it is reasonable to write the distance as positive because the diver is accending/ going up the surface

Kobotan [32]4 years ago

4 0

Answer:

a) d=rt

b) The diver is ascending to point zero

c)3.65 min

Step-by-step explanation:

a) If the diver ascends at 8m/min from 32.12 below sea level we can write an expression if d is the distance, t is the time and r is the rate. This expression can calculate the distance he is below sea level, the rate or the time it takes to reach the surface.

$d=r*t$

where d=m, r=m/min and t=min

b) We can write the distance as a postive number because the diver is 32 m below sea level and he is ascending and not descending below that point. Which means he is ascending to point zero.

c) We can calculate the time with the expression:

$t=d/r$

$t=32.12/8.8=3.65$

The time it takes to reach the surface is 3.63 mins

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