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3 years ago

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2 answers:

Airida [17]3 years ago

7 0

Answer:

Last one

Domain: (−∞, 0)∪ (0, ∞) Range: (−∞, 0)∪ (0, ∞)

Step-by-step explanation:

f(x) = 3/(5x⁵)

Since x is in the denominator, x can not be 0

Domain: all real values of x except 0

For y = 0, x has to be infinite therefore y can not be 0

Range: all real values except 0

MAVERICK [17]3 years ago

4 0

Answer:

Domain: (−∞, 0) ∪ (0, ∞); Range: (−∞, 0) ∪ (0, ∞)

Step-by-step explanation:

See attachment.

We want to find the domain and range of the function $f(x)=\frac{3}{5} x^5$ .

The domain is the set of all possible x-values that are included in the function, while the range is the set of all possible y-values that are included in the function.

Look at the graph.

We can see that the x-values can go into infinity except when approaching the line x = 0. Here, the function will never touch x = 0 because that would make the graph undefined. So, we can say that the domain is all real numbers except for x = 0, or (−∞, 0) ∪ (0, ∞).

It's the same thing with the y-values. Although it looks like the line is touching the y-axis, or the line y = 0, the graph actually is not - it's just going really close to it. So, the range is again (−∞, 0) ∪ (0, ∞).

Thus, the answer is D.

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lina2011 [118]

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Step-by-step explanation:

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y= 4x

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3 years ago

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What is the value of n?

morpeh [17]

Answer:

n = 28 degree

Step-by-step explanation:

2n + 17 + 2n - 5 + 2n = 180 degree (sum of interior angles of a triangle)

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3 years ago

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Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.

Elena-2011 [213]

Answer:

$B - A = -6$

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

$x + 3y = -5$

Subtract x from both sides

$x - x + 3y = -5 - x$

$3y = -5 - x$

Divide both sides by 3

$\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}$

$y = -\frac{5}{3} - \frac{x}{3}$

The slope of the line is the coefficient of x

Slope = $- \frac{1}{3}$

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of $- \frac{1}{3}$

Having calculated the slope, next is to calculate the equation of the line using the following formula;

$m = \frac{y - y_1}{x - x_1}$

Where m is the slope; m = $- \frac{1}{3}$ ; $(x_1, y_1) = (-7,2)$

Substitute these values in the formula above; the formula becomes

$-\frac{1}{3} = \frac{y - 2}{x - -7}$

$-\frac{1}{3} = \frac{y - 2}{x +7}$

Cross Multiply

$-1(x+7) = 3(y-2)$

Open brackets

$-x - 7 = 3y - 6$

Add x to both sides

$x - x - 7 = 3y - 6 + x$

$-7 = 3y - 6 +x$

Add 6 to both sides

$-7 + 6 = 3y -6 + 6 + x$

$-1 = 3y + x$

Multipby both sides by -3

$-3(-1) = -3(3y + x)$

$3 = -9y - 3x$

$-9y - 3x = 3$

$-3x - 9y = 3$

Comparing the above to Ax + By = 3

$Ax = -3x\\A = -3$

$By = -9y\\B = -9$

$B - A = -9 - (-3)$

$B - A = -9 + 3$

$B - A = -6$

3 0

3 years ago