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agasfer [191]
3 years ago
14

2) -8 + 8n + 13 – 6n = 29

Mathematics
2 answers:
Alexxx [7]3 years ago
7 0
Combine like terms so it’s 2n+5=29
Subtract the 5
2n=24 so n=12
lys-0071 [83]3 years ago
6 0
Let’s go!

You combine like terms then complete the multi step equation.

So you would get 5+2n=29

So that equals 17 :)
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State who is correct and explain why
Ivan

Answer:

12.4+3√7 is  irrational

Step-by-step explanation:

12.4 is a rational number

3√7 is an irrational number

<u>The sum of a rational number and an irrational number is irrational.</u>

So, 12.4+3√7 is  irrational

4 0
4 years ago
PLEASE HELP ME I DONT UNDERSTAND.
Bingel [31]

width = 7cm

Length= 41cm

width=x

length=3x+20

96=3x+20+3x+20+x+x

96=8x+40

56=8x

x=8


5 0
3 years ago
Read 2 more answers
A community swimming pool is a rectangular prism that is 30 feet long, 12 feet wide, and 5 feet deep. The wading pool is half as
topjm [15]

Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

Community swimming pool

V_{c} = l\cdot w\cdot h (1)

Wading pool

V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

V_{c} – Volume of the community swimming pool, measured in cubic feet.

V_{w} – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)

\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }

\frac{V_{c}}{V_{w}} = 4

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

8 0
2 years ago
Read 2 more answers
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
4 years ago
:<br> Which is the solution to –7x &gt; 49?
zvonat [6]
X < -7
Hope I could help
8 0
3 years ago
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