Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
Yes they are rational numbers
Step-by-step explanation:
<span>2a^2+ab+5ab+5b^2
2a(a+b) +5b(a+b)
(a+b)(2a+5b)</span>
0.78
hope this helps, good luck! :)
Answer:
305 and 793
Step-by-step explanation:
LCM * HCF = product
3965 * 61 = 241,865 = 5*13*61*61
HCF = 61 so
61*5 = 305
61 * 13 = 793
